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51-(2x+3)=4(x+5)+x
We move all terms to the left:
51-(2x+3)-(4(x+5)+x)=0
We get rid of parentheses
-2x-(4(x+5)+x)-3+51=0
We calculate terms in parentheses: -(4(x+5)+x), so:We add all the numbers together, and all the variables
4(x+5)+x
We add all the numbers together, and all the variables
x+4(x+5)
We multiply parentheses
x+4x+20
We add all the numbers together, and all the variables
5x+20
Back to the equation:
-(5x+20)
-2x-(5x+20)+48=0
We get rid of parentheses
-2x-5x-20+48=0
We add all the numbers together, and all the variables
-7x+28=0
We move all terms containing x to the left, all other terms to the right
-7x=-28
x=-28/-7
x=+4
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