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52+180x^2=26+90
We move all terms to the left:
52+180x^2-(26+90)=0
We add all the numbers together, and all the variables
180x^2+52-116=0
We add all the numbers together, and all the variables
180x^2-64=0
a = 180; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·180·(-64)
Δ = 46080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{46080}=\sqrt{9216*5}=\sqrt{9216}*\sqrt{5}=96\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96\sqrt{5}}{2*180}=\frac{0-96\sqrt{5}}{360} =-\frac{96\sqrt{5}}{360} =-\frac{4\sqrt{5}}{15} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96\sqrt{5}}{2*180}=\frac{0+96\sqrt{5}}{360} =\frac{96\sqrt{5}}{360} =\frac{4\sqrt{5}}{15} $
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