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52/x+3=91/2x-1
We move all terms to the left:
52/x+3-(91/2x-1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x-1)!=0We get rid of parentheses
x∈R
52/x-91/2x+1+3=0
We calculate fractions
104x/2x^2+(-91x)/2x^2+1+3=0
We add all the numbers together, and all the variables
104x/2x^2+(-91x)/2x^2+4=0
We multiply all the terms by the denominator
104x+(-91x)+4*2x^2=0
Wy multiply elements
8x^2+104x+(-91x)=0
We get rid of parentheses
8x^2+104x-91x=0
We add all the numbers together, and all the variables
8x^2+13x=0
a = 8; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·8·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*8}=\frac{-26}{16} =-1+5/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*8}=\frac{0}{16} =0 $
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