520-(30/3)y=100+(50/2)y

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Solution for 520-(30/3)y=100+(50/2)y equation: 



520-(30/3)y=100+(50/2)y

We move all terms to the left:

520-(30/3)y-(100+(50/2)y)=0



Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R





Domain of the equation: 2)y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

-10y-(100+25y)+520=0

We get rid of parentheses

-10y-25y-100+520=0

We add all the numbers together, and all the variables

-35y+420=0

We move all terms containing y to the left, all other terms to the right

-35y=-420

y=-420/-35

y=+12

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