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525=x+2/3x
We move all terms to the left:
525-(x+2/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+x+2/3x)+525=0
We get rid of parentheses
-x-2/3x+525=0
We multiply all the terms by the denominator
-x*3x+525*3x-2=0
Wy multiply elements
-3x^2+1575x-2=0
a = -3; b = 1575; c = -2;
Δ = b2-4ac
Δ = 15752-4·(-3)·(-2)
Δ = 2480601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1575)-\sqrt{2480601}}{2*-3}=\frac{-1575-\sqrt{2480601}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1575)+\sqrt{2480601}}{2*-3}=\frac{-1575+\sqrt{2480601}}{-6} $
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