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52=(2w+8)(w)
We move all terms to the left:
52-((2w+8)(w))=0
We calculate terms in parentheses: -((2w+8)w), so:We get rid of parentheses
(2w+8)w
We multiply parentheses
2w^2+8w
Back to the equation:
-(2w^2+8w)
-2w^2-8w+52=0
a = -2; b = -8; c = +52;
Δ = b2-4ac
Δ = -82-4·(-2)·52
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{30}}{2*-2}=\frac{8-4\sqrt{30}}{-4} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{30}}{2*-2}=\frac{8+4\sqrt{30}}{-4} $
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