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52=(2x-5)x
We move all terms to the left:
52-((2x-5)x)=0
We calculate terms in parentheses: -((2x-5)x), so:We get rid of parentheses
(2x-5)x
We multiply parentheses
2x^2-5x
Back to the equation:
-(2x^2-5x)
-2x^2+5x+52=0
a = -2; b = 5; c = +52;
Δ = b2-4ac
Δ = 52-4·(-2)·52
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-21}{2*-2}=\frac{-26}{-4} =6+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+21}{2*-2}=\frac{16}{-4} =-4 $
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