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52=9/5c
We move all terms to the left:
52-(9/5c)=0
Domain of the equation: 5c)!=0We add all the numbers together, and all the variables
c!=0/1
c!=0
c∈R
-(+9/5c)+52=0
We get rid of parentheses
-9/5c+52=0
We multiply all the terms by the denominator
52*5c-9=0
Wy multiply elements
260c-9=0
We move all terms containing c to the left, all other terms to the right
260c=9
c=9/260
c=9/260
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