52x+20x*x=0

Solution for 52x+20x*x=0 equation:

52x+20x*x=0

Wy multiply elements

20x^2+52x=0

a = 20; b = 52; c = 0;
Δ = b2-4ac
Δ = 522-4·20·0
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-52}{2*20}=\frac{-104}{40}
=-2+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+52}{2*20}=\frac{0}{40}
=0
$