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53/5=-33/5n+1+2n
We move all terms to the left:
53/5-(-33/5n+1+2n)=0
Domain of the equation: 5n+1+2n)!=0We add all the numbers together, and all the variables
We move all terms containing n to the left, all other terms to the right
5n+2n)!=-1
n∈R
-(2n-33/5n+1)+53/5=0
We get rid of parentheses
-2n+33/5n-1+53/5=0
We calculate fractions
-2n-1=0
We move all terms containing n to the left, all other terms to the right
-2n=1
n=1/-2
n=-1/2
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