53=4r+3(1+2r)

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Solution for 53=4r+3(1+2r) equation: 



53=4r+3(1+2r)

We move all terms to the left:

53-(4r+3(1+2r))=0

We add all the numbers together, and all the variables

-(4r+3(2r+1))+53=0



We calculate terms in parentheses: -(4r+3(2r+1)), so:

4r+3(2r+1)

We multiply parentheses

4r+6r+3

We add all the numbers together, and all the variables

10r+3

Back to the equation:

-(10r+3)



We get rid of parentheses

-10r-3+53=0

We add all the numbers together, and all the variables

-10r+50=0

We move all terms containing r to the left, all other terms to the right

-10r=-50

r=-50/-10

r=+5

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