540=((5x+2)+(5x+10)+(3x+5)+(8x+8)+(4x+15))

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Solution for 540=((5x+2)+(5x+10)+(3x+5)+(8x+8)+(4x+15)) equation: 



540=((5x+2)+(5x+10)+(3x+5)+(8x+8)+(4x+15))

We move all terms to the left:

540-(((5x+2)+(5x+10)+(3x+5)+(8x+8)+(4x+15)))=0



We calculate terms in parentheses: -(((5x+2)+(5x+10)+(3x+5)+(8x+8)+(4x+15))), so:

((5x+2)+(5x+10)+(3x+5)+(8x+8)+(4x+15))



We calculate terms in parentheses: +((5x+2)+(5x+10)+(3x+5)+(8x+8)+(4x+15)), so:

(5x+2)+(5x+10)+(3x+5)+(8x+8)+(4x+15)

We get rid of parentheses

5x+5x+3x+8x+4x+2+10+5+8+15

We add all the numbers together, and all the variables

25x+40

Back to the equation:

+(25x+40)



We get rid of parentheses

25x+40

Back to the equation:

-(25x+40)



We get rid of parentheses

-25x-40+540=0

We add all the numbers together, and all the variables

-25x+500=0

We move all terms containing x to the left, all other terms to the right

-25x=-500

x=-500/-25

x=+20

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