540=(3x+5)+(4x-10)+(4x-15)

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Solution for 540=(3x+5)+(4x-10)+(4x-15) equation: 



540=(3x+5)+(4x-10)+(4x-15)

We move all terms to the left:

540-((3x+5)+(4x-10)+(4x-15))=0



We calculate terms in parentheses: -((3x+5)+(4x-10)+(4x-15)), so:

(3x+5)+(4x-10)+(4x-15)

We get rid of parentheses

3x+4x+4x+5-10-15

We add all the numbers together, and all the variables

11x-20

Back to the equation:

-(11x-20)



We get rid of parentheses

-11x+20+540=0

We add all the numbers together, and all the variables

-11x+560=0

We move all terms containing x to the left, all other terms to the right

-11x=-560

x=-560/-11

x=50+10/11

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