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540=139+(3x)+(5x-10)+(10x-9)+(3x)
We move all terms to the left:
540-(139+(3x)+(5x-10)+(10x-9)+(3x))=0
We calculate terms in parentheses: -(139+3x+(5x-10)+(10x-9)+3x), so:We get rid of parentheses
139+3x+(5x-10)+(10x-9)+3x
determiningTheFunctionDomain 3x+(5x-10)+(10x-9)+3x+139
We add all the numbers together, and all the variables
6x+(5x-10)+(10x-9)+139
We get rid of parentheses
6x+5x+10x-10-9+139
We add all the numbers together, and all the variables
21x+120
Back to the equation:
-(21x+120)
-21x-120+540=0
We add all the numbers together, and all the variables
-21x+420=0
We move all terms containing x to the left, all other terms to the right
-21x=-420
x=-420/-21
x=+20
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