540=2x+142+2x+(3x+14)+(3x+14)

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Solution for 540=2x+142+2x+(3x+14)+(3x+14) equation: 



540=2x+142+2x+(3x+14)+(3x+14)

We move all terms to the left:

540-(2x+142+2x+(3x+14)+(3x+14))=0



We calculate terms in parentheses: -(2x+142+2x+(3x+14)+(3x+14)), so:

2x+142+2x+(3x+14)+(3x+14)

determiningTheFunctionDomain
2x+2x+(3x+14)+(3x+14)+142

We add all the numbers together, and all the variables

4x+(3x+14)+(3x+14)+142

We get rid of parentheses

4x+3x+3x+14+14+142

We add all the numbers together, and all the variables

10x+170

Back to the equation:

-(10x+170)



We get rid of parentheses

-10x-170+540=0

We add all the numbers together, and all the variables

-10x+370=0

We move all terms containing x to the left, all other terms to the right

-10x=-370

x=-370/-10

x=+37

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