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540=3/5x^2
We move all terms to the left:
540-(3/5x^2)=0
Domain of the equation: 5x^2)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
-3/5x^2+540=0
We multiply all the terms by the denominator
540*5x^2-3=0
Wy multiply elements
2700x^2-3=0
a = 2700; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·2700·(-3)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*2700}=\frac{-180}{5400} =-1/30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*2700}=\frac{180}{5400} =1/30 $
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