540=90+(2b-90)+(3/2b)+b+(b-45)

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Solution for 540=90+(2b-90)+(3/2b)+b+(b-45) equation: 


b in (-oo:+oo)

540 = 2*b+(3/2)*b+b+b-90-45+90 // - 2*b+(3/2)*b+b+b-90-45+90

45-(2*b)-((3/2)*b)-b-b-90+90+540 = 0

(-3/2)*b-2*b-b-b-90+45+90+540 = 0

585-11/2*b = 0 // - 585

-11/2*b = -585 // : -11/2

b = -585/(-11/2)

b = 1170/11

b = 1170/11

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