540=b+(b+45)+90+(2b-90)+1.5b

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Solution for 540=b+(b+45)+90+(2b-90)+1.5b equation: 



540=b+(b+45)+90+(2b-90)+1.5b

We move all terms to the left:

540-(b+(b+45)+90+(2b-90)+1.5b)=0



We calculate terms in parentheses: -(b+(b+45)+90+(2b-90)+1.5b), so:

b+(b+45)+90+(2b-90)+1.5b

determiningTheFunctionDomain
b+(b+45)+(2b-90)+1.5b+90

We add all the numbers together, and all the variables

2.5b+(b+45)+(2b-90)+90

We get rid of parentheses

2.5b+b+2b+45-90+90

We add all the numbers together, and all the variables

5.5b+45

Back to the equation:

-(5.5b+45)



We get rid of parentheses

-5.5b-45+540=0

We add all the numbers together, and all the variables

-5.5b+495=0

We move all terms containing b to the left, all other terms to the right

-5.5b=-495

b=-495/-5.5

b=+90

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