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54=v2
We move all terms to the left:
54-(v2)=0
We add all the numbers together, and all the variables
-1v^2+54=0
a = -1; b = 0; c = +54;
Δ = b2-4ac
Δ = 02-4·(-1)·54
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{6}}{2*-1}=\frac{0-6\sqrt{6}}{-2} =-\frac{6\sqrt{6}}{-2} =-\frac{3\sqrt{6}}{-1} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{6}}{2*-1}=\frac{0+6\sqrt{6}}{-2} =\frac{6\sqrt{6}}{-2} =\frac{3\sqrt{6}}{-1} $
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