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54t-9t^2=0
a = -9; b = 54; c = 0;
Δ = b2-4ac
Δ = 542-4·(-9)·0
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-54}{2*-9}=\frac{-108}{-18} =+6 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+54}{2*-9}=\frac{0}{-18} =0 $
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