55-(10-2x)=43+(4x-2)

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Solution for 55-(10-2x)=43+(4x-2) equation: 



55-(10-2x)=43+(4x-2)

We move all terms to the left:

55-(10-2x)-(43+(4x-2))=0

We add all the numbers together, and all the variables

-(-2x+10)-(43+(4x-2))+55=0

We get rid of parentheses

2x-(43+(4x-2))-10+55=0



We calculate terms in parentheses: -(43+(4x-2)), so:

43+(4x-2)

determiningTheFunctionDomain
(4x-2)+43

We get rid of parentheses

4x-2+43

We add all the numbers together, and all the variables

4x+41

Back to the equation:

-(4x+41)



We add all the numbers together, and all the variables

2x-(4x+41)+45=0

We get rid of parentheses

2x-4x-41+45=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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