55=(2+x)(4-x)

Solution for 55=(2+x)(4-x) equation:

55=(2+x)(4-x)

We move all terms to the left:

55-((2+x)(4-x))=0

We add all the numbers together, and all the variables

-((x+2)(-1x+4))+55=0

We multiply parentheses ..

-((-1x^2+4x-2x+8))+55=0


We calculate terms in parentheses: -((-1x^2+4x-2x+8)), so:

(-1x^2+4x-2x+8)

We get rid of parentheses

-1x^2+4x-2x+8

We add all the numbers together, and all the variables

-1x^2+2x+8

Back to the equation:

-(-1x^2+2x+8)


We get rid of parentheses

1x^2-2x-8+55=0

We add all the numbers together, and all the variables

x^2-2x+47=0

a = 1; b = -2; c = +47;
Δ = b2-4ac
Δ = -22-4·1·47
Δ = -184
Delta is less than zero, so there is no solution for the equation