55=50+((n-40)/4)

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Solution for 55=50+((n-40)/4) equation:



55=50+((n-40)/4)
We move all terms to the left:
55-(50+((n-40)/4))=0
We multiply all the terms by the denominator
-(50+((n-40)+55*4))=0
We calculate terms in parentheses: -(50+((n-40)+55*4)), so:
50+((n-40)+55*4)
determiningTheFunctionDomain ((n-40)+55*4)+50
We calculate terms in parentheses: +((n-40)+55*4), so:
(n-40)+55*4
We add all the numbers together, and all the variables
(n-40)+220
We get rid of parentheses
n-40+220
We add all the numbers together, and all the variables
n+180
Back to the equation:
+(n+180)
We get rid of parentheses
n+180+50
We add all the numbers together, and all the variables
n+230
Back to the equation:
-(n+230)
We get rid of parentheses
-n-230=0
We add all the numbers together, and all the variables
-1n-230=0
We move all terms containing n to the left, all other terms to the right
-n=230
n=230/-1
n=-230

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