55d+2(2-d)=3(1+d)+1

Solution for 55d+2(2-d)=3(1+d)+1 equation:

55d+2(2-d)=3(1+d)+1

We move all terms to the left:

55d+2(2-d)-(3(1+d)+1)=0

We add all the numbers together, and all the variables

55d+2(-1d+2)-(3(d+1)+1)=0

We multiply parentheses

55d-2d-(3(d+1)+1)+4=0


We calculate terms in parentheses: -(3(d+1)+1), so:

3(d+1)+1

We multiply parentheses

3d+3+1

We add all the numbers together, and all the variables

3d+4

Back to the equation:

-(3d+4)


We add all the numbers together, and all the variables

53d-(3d+4)+4=0

We get rid of parentheses

53d-3d-4+4=0

We add all the numbers together, and all the variables

50d=0

d=0/50

d=0