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55x-3x(2x-12)=-64
We move all terms to the left:
55x-3x(2x-12)-(-64)=0
We add all the numbers together, and all the variables
55x-3x(2x-12)+64=0
We multiply parentheses
-6x^2+55x+36x+64=0
We add all the numbers together, and all the variables
-6x^2+91x+64=0
a = -6; b = 91; c = +64;
Δ = b2-4ac
Δ = 912-4·(-6)·64
Δ = 9817
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(91)-\sqrt{9817}}{2*-6}=\frac{-91-\sqrt{9817}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(91)+\sqrt{9817}}{2*-6}=\frac{-91+\sqrt{9817}}{-12} $
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