56(2c+4)=4(c+6)+c

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Solution for 56(2c+4)=4(c+6)+c equation: 



56(2c+4)=4(c+6)+c

We move all terms to the left:

56(2c+4)-(4(c+6)+c)=0

We multiply parentheses

112c-(4(c+6)+c)+224=0



We calculate terms in parentheses: -(4(c+6)+c), so:

4(c+6)+c

We add all the numbers together, and all the variables

c+4(c+6)

We multiply parentheses

c+4c+24

We add all the numbers together, and all the variables

5c+24

Back to the equation:

-(5c+24)



We get rid of parentheses

112c-5c-24+224=0

We add all the numbers together, and all the variables

107c+200=0

We move all terms containing c to the left, all other terms to the right

107c=-200

c=-200/107

c=-1+93/107

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