56(b+79)-71b-56=b-12+46b-96

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Solution for 56(b+79)-71b-56=b-12+46b-96 equation:



56(b+79)-71b-56=b-12+46b-96
We move all terms to the left:
56(b+79)-71b-56-(b-12+46b-96)=0
We add all the numbers together, and all the variables
56(b+79)-71b-(47b-108)-56=0
We add all the numbers together, and all the variables
-71b+56(b+79)-(47b-108)-56=0
We multiply parentheses
-71b+56b-(47b-108)+4424-56=0
We get rid of parentheses
-71b+56b-47b+108+4424-56=0
We add all the numbers together, and all the variables
-62b+4476=0
We move all terms containing b to the left, all other terms to the right
-62b=-4476
b=-4476/-62
b=72+6/31

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