56+(6-3b)=12

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Solution for 56+(6-3b)=12 equation: 



56+(6-3b)=12

We move all terms to the left:

56+(6-3b)-(12)=0

We add all the numbers together, and all the variables

(-3b+6)+56-12=0

We add all the numbers together, and all the variables

(-3b+6)+44=0

We get rid of parentheses

-3b+6+44=0

We add all the numbers together, and all the variables

-3b+50=0

We move all terms containing b to the left, all other terms to the right

-3b=-50

b=-50/-3

b=16+2/3

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