56-(3c+4)=4(c+7)+7

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Solution for 56-(3c+4)=4(c+7)+7 equation:



56-(3c+4)=4(c+7)+7
We move all terms to the left:
56-(3c+4)-(4(c+7)+7)=0
We get rid of parentheses
-3c-(4(c+7)+7)-4+56=0
We calculate terms in parentheses: -(4(c+7)+7), so:
4(c+7)+7
We multiply parentheses
4c+28+7
We add all the numbers together, and all the variables
4c+35
Back to the equation:
-(4c+35)
We add all the numbers together, and all the variables
-3c-(4c+35)+52=0
We get rid of parentheses
-3c-4c-35+52=0
We add all the numbers together, and all the variables
-7c+17=0
We move all terms containing c to the left, all other terms to the right
-7c=-17
c=-17/-7
c=2+3/7

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