560=x*(2x-3)

Solution for 560=x*(2x-3) equation:

560=x(2x-3)

We move all terms to the left:

560-(x(2x-3))=0


We calculate terms in parentheses: -(x(2x-3)), so:

x(2x-3)

We multiply parentheses

2x^2-3x

Back to the equation:

-(2x^2-3x)


We get rid of parentheses

-2x^2+3x+560=0

a = -2; b = 3; c = +560;
Δ = b2-4ac
Δ = 32-4·(-2)·560
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4489}=67$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-67}{2*-2}=\frac{-70}{-4}
=17+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+67}{2*-2}=\frac{64}{-4}
=-16
$