56=4(2+3b)

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Solution for 56=4(2+3b) equation:



56=4(2+3b)
We move all terms to the left:
56-(4(2+3b))=0
We add all the numbers together, and all the variables
-(4(3b+2))+56=0
We calculate terms in parentheses: -(4(3b+2)), so:
4(3b+2)
We multiply parentheses
12b+8
Back to the equation:
-(12b+8)
We get rid of parentheses
-12b-8+56=0
We add all the numbers together, and all the variables
-12b+48=0
We move all terms containing b to the left, all other terms to the right
-12b=-48
b=-48/-12
b=+4

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