56=4(3x-2)+2(x+4)

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Solution for 56=4(3x-2)+2(x+4) equation: 



56=4(3x-2)+2(x+4)

We move all terms to the left:

56-(4(3x-2)+2(x+4))=0



We calculate terms in parentheses: -(4(3x-2)+2(x+4)), so:

4(3x-2)+2(x+4)

We multiply parentheses

12x+2x-8+8

We add all the numbers together, and all the variables

14x

Back to the equation:

-(14x)



We move all terms containing x to the left, all other terms to the right

-14x=-56

x=-56/-14

x=+4

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