56=4(b+3)

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Solution for 56=4(b+3) equation: 



56=4(b+3)

We move all terms to the left:

56-(4(b+3))=0



We calculate terms in parentheses: -(4(b+3)), so:

4(b+3)

We multiply parentheses

4b+12

Back to the equation:

-(4b+12)



We get rid of parentheses

-4b-12+56=0

We add all the numbers together, and all the variables

-4b+44=0

We move all terms containing b to the left, all other terms to the right

-4b=-44

b=-44/-4

b=+11

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