56=4z+12

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Solution for 56=4z+12 equation: 



56=4z+12

We move all terms to the left:

56-(4z+12)=0

We get rid of parentheses

-4z-12+56=0

We add all the numbers together, and all the variables

-4z+44=0

We move all terms containing z to the left, all other terms to the right

-4z=-44

z=-44/-4

z=+11

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