56x2-113x+56=0

Solution for 56x2-113x+56=0 equation:

56x^2-113x+56=0

a = 56; b = -113; c = +56;
Δ = b2-4ac
Δ = -1132-4·56·56
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-113)-15}{2*56}=\frac{98}{112}
=7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-113)+15}{2*56}=\frac{128}{112}
=1+1/7
$