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56x^2=21
We move all terms to the left:
56x^2-(21)=0
a = 56; b = 0; c = -21;
Δ = b2-4ac
Δ = 02-4·56·(-21)
Δ = 4704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4704}=\sqrt{784*6}=\sqrt{784}*\sqrt{6}=28\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-28\sqrt{6}}{2*56}=\frac{0-28\sqrt{6}}{112} =-\frac{28\sqrt{6}}{112} =-\frac{\sqrt{6}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+28\sqrt{6}}{2*56}=\frac{0+28\sqrt{6}}{112} =\frac{28\sqrt{6}}{112} =\frac{\sqrt{6}}{4} $
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