56x=8x2+98

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Solution for 56x=8x2+98 equation: 



56x=8x^2+98

We move all terms to the left:

56x-(8x^2+98)=0

We get rid of parentheses

-8x^2+56x-98=0

a = -8; b = 56; c = -98;
Δ = b2-4ac
Δ = 562-4·(-8)·(-98)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-56}{-16}=3+1/2$

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