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576/2l+2l=68
We move all terms to the left:
576/2l+2l-(68)=0
Domain of the equation: 2l!=0We add all the numbers together, and all the variables
l!=0/2
l!=0
l∈R
2l+576/2l-68=0
We multiply all the terms by the denominator
2l*2l-68*2l+576=0
Wy multiply elements
4l^2-136l+576=0
a = 4; b = -136; c = +576;
Δ = b2-4ac
Δ = -1362-4·4·576
Δ = 9280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$l_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$l_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9280}=\sqrt{64*145}=\sqrt{64}*\sqrt{145}=8\sqrt{145}$$l_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-136)-8\sqrt{145}}{2*4}=\frac{136-8\sqrt{145}}{8} $$l_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-136)+8\sqrt{145}}{2*4}=\frac{136+8\sqrt{145}}{8} $
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