57=1/2(x-40x+3)

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Solution for 57=1/2(x-40x+3) equation: 



57=1/2(x-40x+3)

We move all terms to the left:

57-(1/2(x-40x+3))=0



Domain of the equation: 2(x-40x+3))!=0

x∈R



We add all the numbers together, and all the variables

-(1/2(-39x+3))+57=0

We multiply all the terms by the denominator


-(1+57*2(-39x+3))=0



We calculate terms in parentheses: -(1+57*2(-39x+3)), so:

1+57*2(-39x+3)

determiningTheFunctionDomain
57*2(-39x+3)+1

Wy multiply elements

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We use the square of the difference formula

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