57=3(4v+1)+2v

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Solution for 57=3(4v+1)+2v equation: 



57=3(4v+1)+2v

We move all terms to the left:

57-(3(4v+1)+2v)=0



We calculate terms in parentheses: -(3(4v+1)+2v), so:

3(4v+1)+2v

We add all the numbers together, and all the variables

2v+3(4v+1)

We multiply parentheses

2v+12v+3

We add all the numbers together, and all the variables

14v+3

Back to the equation:

-(14v+3)



We get rid of parentheses

-14v-3+57=0

We add all the numbers together, and all the variables

-14v+54=0

We move all terms containing v to the left, all other terms to the right

-14v=-54

v=-54/-14

v=3+6/7

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