57=32-5(x-2)

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Solution for 57=32-5(x-2) equation: 



57=32-5(x-2)

We move all terms to the left:

57-(32-5(x-2))=0



We calculate terms in parentheses: -(32-5(x-2)), so:

32-5(x-2)

determiningTheFunctionDomain
-5(x-2)+32

We multiply parentheses

-5x+10+32

We add all the numbers together, and all the variables

-5x+42

Back to the equation:

-(-5x+42)



We get rid of parentheses

5x-42+57=0

We add all the numbers together, and all the variables

5x+15=0

We move all terms containing x to the left, all other terms to the right

5x=-15

x=-15/5

x=-3

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