57k=4(k+1)3

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Solution for 57k=4(k+1)3 equation: 



57k=4(k+1)3

We move all terms to the left:

57k-(4(k+1)3)=0



We calculate terms in parentheses: -(4(k+1)3), so:

4(k+1)3

We multiply parentheses

12k+12

Back to the equation:

-(12k+12)



We get rid of parentheses

57k-12k-12=0

We add all the numbers together, and all the variables

45k-12=0

We move all terms containing k to the left, all other terms to the right

45k=12

k=12/45

k=4/15

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