57y=14(4y+10)

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Solution for 57y=14(4y+10) equation: 



57y=14(4y+10)

We move all terms to the left:

57y-(14(4y+10))=0



We calculate terms in parentheses: -(14(4y+10)), so:

14(4y+10)

We multiply parentheses

56y+140

Back to the equation:

-(56y+140)



We get rid of parentheses

57y-56y-140=0

We add all the numbers together, and all the variables

y-140=0

We move all terms containing y to the left, all other terms to the right

y=140

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