58-(2c+3)=4(c+5)+4

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Solution for 58-(2c+3)=4(c+5)+4 equation: 



58-(2c+3)=4(c+5)+4

We move all terms to the left:

58-(2c+3)-(4(c+5)+4)=0

We get rid of parentheses

-2c-(4(c+5)+4)-3+58=0



We calculate terms in parentheses: -(4(c+5)+4), so:

4(c+5)+4

We multiply parentheses

4c+20+4

We add all the numbers together, and all the variables

4c+24

Back to the equation:

-(4c+24)



We add all the numbers together, and all the variables

-2c-(4c+24)+55=0

We get rid of parentheses

-2c-4c-24+55=0

We add all the numbers together, and all the variables

-6c+31=0

We move all terms containing c to the left, all other terms to the right

-6c=-31

c=-31/-6

c=5+1/6

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