58000/20(x)+10(x)+10+2000=3731

Solution for 58000/20(x)+10(x)+10+2000=3731 equation:

58000/20(x)+10(x)+10+2000=3731

We move all terms to the left:

58000/20(x)+10(x)+10+2000-(3731)=0


Domain of the equation: 20x!=0

x!=0/20

x!=0

x∈R


We add all the numbers together, and all the variables

10x+58000/20x-1721=0

We multiply all the terms by the denominator


10x*20x-1721*20x+58000=0

Wy multiply elements

200x^2-34420x+58000=0

a = 200; b = -34420; c = +58000;
Δ = b2-4ac
Δ = -344202-4·200·58000
Δ = 1138336400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1138336400}=\sqrt{400*2845841}=\sqrt{400}*\sqrt{2845841}=20\sqrt{2845841}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34420)-20\sqrt{2845841}}{2*200}=\frac{34420-20\sqrt{2845841}}{400}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34420)+20\sqrt{2845841}}{2*200}=\frac{34420+20\sqrt{2845841}}{400}
$