58=(a)+2(b)+(c)

Solution for 58=(a)+2(b)+(c) equation:

Simplifying
58 = (a) + 2(b) + (c)
58 = a + 2(b) + (c)
58 = a + 2b + c

Solving
58 = a + 2b + c

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1a' to each side of the equation.
58 + -1a = a + 2b + -1a + c

Reorder the terms:
58 + -1a = a + -1a + 2b + c

Combine like terms: a + -1a = 0
58 + -1a = 0 + 2b + c
58 + -1a = 2b + c

Add '-58' to each side of the equation.
58 + -58 + -1a = 2b + -58 + c

Combine like terms: 58 + -58 = 0
0 + -1a = 2b + -58 + c
-1a = 2b + -58 + c

Reorder the terms:
-1a = -58 + 2b + c

Divide each side by '-1'.
a = 58 + -2b + -1c

Simplifying
a = 58 + -2b + -1c