58=-3(4v+1)+2v

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Solution for 58=-3(4v+1)+2v equation: 



58=-3(4v+1)+2v

We move all terms to the left:

58-(-3(4v+1)+2v)=0



We calculate terms in parentheses: -(-3(4v+1)+2v), so:

-3(4v+1)+2v

We add all the numbers together, and all the variables

2v-3(4v+1)

We multiply parentheses

2v-12v-3

We add all the numbers together, and all the variables

-10v-3

Back to the equation:

-(-10v-3)



We get rid of parentheses

10v+3+58=0

We add all the numbers together, and all the variables

10v+61=0

We move all terms containing v to the left, all other terms to the right

10v=-61

v=-61/10

v=-6+1/10

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