58=-8(2x+4)+6x

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Solution for 58=-8(2x+4)+6x equation: 



58=-8(2x+4)+6x

We move all terms to the left:

58-(-8(2x+4)+6x)=0



We calculate terms in parentheses: -(-8(2x+4)+6x), so:

-8(2x+4)+6x

We add all the numbers together, and all the variables

6x-8(2x+4)

We multiply parentheses

6x-16x-32

We add all the numbers together, and all the variables

-10x-32

Back to the equation:

-(-10x-32)



We get rid of parentheses

10x+32+58=0

We add all the numbers together, and all the variables

10x+90=0

We move all terms containing x to the left, all other terms to the right

10x=-90

x=-90/10

x=-9

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