58=1A+2B+1C

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Solution for 58=1A+2B+1C equation:


Simplifying
58 = 1A + 2B + 1C

Solving
58 = 1A + 2B + 1C

Solving for variable 'A'.

Move all terms containing A to the left, all other terms to the right.

Add '-1A' to each side of the equation.
58 + -1A = 1A + 2B + -1A + 1C

Reorder the terms:
58 + -1A = 1A + -1A + 2B + 1C

Combine like terms: 1A + -1A = 0
58 + -1A = 0 + 2B + 1C
58 + -1A = 2B + 1C

Add '-58' to each side of the equation.
58 + -58 + -1A = 2B + -58 + 1C

Combine like terms: 58 + -58 = 0
0 + -1A = 2B + -58 + 1C
-1A = 2B + -58 + 1C

Reorder the terms:
-1A = -58 + 2B + 1C

Divide each side by '-1'.
A = 58 + -2B + -1C

Simplifying
A = 58 + -2B + -1C

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