59(1+c)=6(2+c)

Solution for 59(1+c)=6(2+c) equation:

59(1+c)=6(2+c)

We move all terms to the left:

59(1+c)-(6(2+c))=0

We add all the numbers together, and all the variables

59(c+1)-(6(c+2))=0

We multiply parentheses

59c-(6(c+2))+59=0


We calculate terms in parentheses: -(6(c+2)), so:

6(c+2)

We multiply parentheses

6c+12

Back to the equation:

-(6c+12)


We get rid of parentheses

59c-6c-12+59=0

We add all the numbers together, and all the variables

53c+47=0

We move all terms containing c to the left, all other terms to the right

53c=-47

c=-47/53

c=-47/53